The correct order of the bond angle for the g | vedclass

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Question

(A) To determine the bond angle,we consider the steric repulsion between the groups attached to the oxygen atom.$1$. In $CH_3-O-CH_3$ (dimethyl ether)

Vedclass · Accepted Answer

$CH_3-O-CH_3 > Ph-OH > CH_3-OH$

Vedclass · Answer

(A) To determine the bond angle,we consider the steric repulsion between the groups attached to the oxygen atom.$1$. In $CH_3-O-CH_3$ (dimethyl ether),there are two bulky methyl groups attached to the oxygen. The steric repulsion between these two methyl groups increases the bond angle to approximately $111.7^\circ$.$2$. In $Ph-OH$ (phenol),the oxygen is attached to a phenyl group and a hydrogen atom. The resonance effect of the phenyl ring and the steric bulk of the phenyl group result in a bond angle of approximately $109^\circ$.$3$. In $CH_3-OH$ (methanol),the oxygen is attached to a methyl group and a hydrogen atom. The steric repulsion is less than in the other two cases,resulting in a bond angle of approximately $108.9^\circ$.Therefore,the correct order of bond angle is $CH_3-O-CH_3 > Ph-OH > CH_3-OH$.

The correct order of the bond angle for the given bond is:

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